{"id":20675,"date":"2026-01-05T09:26:50","date_gmt":"2026-01-05T01:26:50","guid":{"rendered":"https:\/\/3d-universal.com\/en\/?p=20675"},"modified":"2026-01-05T09:46:02","modified_gmt":"2026-01-05T01:46:02","slug":"states-of-matter-and-gas-laws","status":"publish","type":"post","link":"https:\/\/3d-universal.com\/en\/blogs\/states-of-matter-and-gas-laws.html","title":{"rendered":"States of Matter and Gas Laws: NMAT Chemistry Review"},"content":{"rendered":"<p><!--more--><\/p>\n<h1>States of Matter and Gas Laws: NMAT Chemistry Review<\/h1>\n<p>Understanding the states of matter and gas laws is a high-yield topic for the NMAT because it connects microscopic particle behavior to macroscopic properties you can measure (pressure, volume, temperature, and moles). Many NMAT questions test whether you can interpret particle motion, phase changes, and apply gas-law relationships quickly and correctly. This review builds a strong foundation: how solids, liquids, and gases differ; how phase transitions work; and how to solve common gas-law problems, including ideal and real gas behavior.<\/p>\n<h2>States of Matter: Particle View and Key Properties<\/h2>\n<p>Matter is classified into states based on how particles are arranged and how strongly they interact. The major states for NMAT chemistry are solid, liquid, and gas (with plasma sometimes mentioned conceptually).<\/p>\n<p><strong>Solids<\/strong> have particles packed closely in fixed positions (especially in crystalline solids). They have:<\/p>\n<ul>\n<li><strong>Definite shape and definite volume<\/strong><\/li>\n<li><strong>Low compressibility<\/strong> (particles are already tightly packed)<\/li>\n<li><strong>High density<\/strong> relative to liquids and gases<\/li>\n<li><strong>Small particle motion<\/strong>: mainly vibrations around fixed points<\/li>\n<\/ul>\n<p><strong>Liquids<\/strong> have particles close together but not fixed; they slide past one another. They have:<\/p>\n<ul>\n<li><strong>Definite volume<\/strong> but <strong>no definite shape<\/strong> (take the shape of the container)<\/li>\n<li><strong>Low compressibility<\/strong><\/li>\n<li><strong>Moderate density<\/strong><\/li>\n<li><strong>Fluidity<\/strong> because particles can move around<\/li>\n<\/ul>\n<p><strong>Gases<\/strong> have particles far apart with minimal intermolecular attraction in most conditions. They have:<\/p>\n<ul>\n<li><strong>No definite shape and no definite volume<\/strong> (expand to fill container)<\/li>\n<li><strong>High compressibility<\/strong><\/li>\n<li><strong>Low density<\/strong><\/li>\n<li><strong>Rapid, random motion<\/strong> with frequent collisions<\/li>\n<\/ul>\n<p><strong>Plasma<\/strong> is an ionized gas with free electrons and ions. It appears in stars, lightning, and neon signs. For NMAT, plasma is usually conceptual rather than computational.<\/p>\n<p><strong>Common NMAT trick:<\/strong> If you increase temperature, particle kinetic energy increases. This affects gas pressure, liquid evaporation, and solid vibration intensity, but compressibility trends remain: gas &gt;&gt; liquid \u2248 solid.<\/p>\n<h2>Intermolecular Forces and Their Role in Phases<\/h2>\n<p>Intermolecular forces (IMFs) are attractions between molecules and strongly influence melting\/boiling points, viscosity, and surface tension. Stronger IMFs typically mean higher boiling points and lower vapor pressures.<\/p>\n<ul>\n<li><strong>London dispersion forces<\/strong>: present in all substances; strongest in larger, more polarizable molecules.<\/li>\n<li><strong>Dipole\u2013dipole forces<\/strong>: between polar molecules; moderate strength.<\/li>\n<li><strong>Hydrogen bonding<\/strong>: a strong dipole\u2013dipole interaction when H is bonded to N, O, or F; leads to unusually high boiling points (e.g., water).<\/li>\n<\/ul>\n<p><strong>Link to states of matter:<\/strong> solids and liquids exist when IMFs can hold particles near each other. Gases dominate when kinetic energy (temperature) overcomes IMFs.<\/p>\n<h2>Phase Changes and Heating Curves<\/h2>\n<p>Phase changes occur when matter transitions between solid, liquid, and gas. Key transitions include:<\/p>\n<ul>\n<li><strong>Melting (fusion)<\/strong>: solid \u2192 liquid<\/li>\n<li><strong>Freezing<\/strong>: liquid \u2192 solid<\/li>\n<li><strong>Vaporization<\/strong>: liquid \u2192 gas (includes boiling and evaporation)<\/li>\n<li><strong>Condensation<\/strong>: gas \u2192 liquid<\/li>\n<li><strong>Sublimation<\/strong>: solid \u2192 gas<\/li>\n<li><strong>Deposition<\/strong>: gas \u2192 solid<\/li>\n<\/ul>\n<p>In a <strong>heating curve<\/strong>, temperature changes during warming within a phase, but stays constant during phase changes because energy goes into overcoming IMFs rather than increasing kinetic energy.<\/p>\n<p><strong>Energy and heat terms:<\/strong><\/p>\n<ul>\n<li><strong>Endothermic<\/strong> (absorbs heat): melting, vaporization, sublimation<\/li>\n<li><strong>Exothermic<\/strong> (releases heat): freezing, condensation, deposition<\/li>\n<\/ul>\n<p><strong>Boiling vs evaporation:<\/strong> evaporation occurs at the surface at any temperature; boiling occurs throughout the liquid at the boiling point when vapor pressure equals external pressure.<\/p>\n<h2>Pressure, Temperature, and Units You Must Know<\/h2>\n<p>Gas laws rely heavily on correct units. NMAT frequently tests unit conversions and understanding of what pressure and temperature represent.<\/p>\n<p><strong>Temperature<\/strong>: Use Kelvin for gas laws.<\/p>\n<ul>\n<li>K = \u00b0C + 273 (more precisely +273.15)<\/li>\n<\/ul>\n<p><strong>Pressure<\/strong> commonly appears in:<\/p>\n<ul>\n<li>atm<\/li>\n<li>mmHg (or torr)<\/li>\n<li>kPa<\/li>\n<\/ul>\n<p><strong>Useful equivalences:<\/strong><\/p>\n<ul>\n<li>1 atm = 760 mmHg = 760 torr<\/li>\n<li>1 atm \u2248 101.3 kPa<\/li>\n<\/ul>\n<p><strong>Volume<\/strong> is typically in liters (L) or milliliters (mL). Remember: 1 L = 1000 mL.<\/p>\n<p><strong>What is pressure?<\/strong> It is force per unit area caused by gas particle collisions with container walls. Higher temperature increases collision frequency\/force; smaller volume increases collision frequency.<\/p>\n<h2>Kinetic Molecular Theory (KMT): The Ideal Gas Model<\/h2>\n<p>Kinetic Molecular Theory describes how ideal gases behave. The ideal gas is a simplified model that works best at high temperature and low pressure.<\/p>\n<p><strong>Key assumptions of an ideal gas:<\/strong><\/p>\n<ul>\n<li>Gas particles have negligible volume compared to the container.<\/li>\n<li>No intermolecular attractions or repulsions exist between particles.<\/li>\n<li>Particles move randomly in straight lines and collide elastically (no net energy loss).<\/li>\n<li>Average kinetic energy depends only on absolute temperature.<\/li>\n<\/ul>\n<p><strong>High-yield implication:<\/strong> If two gases are at the same temperature, their particles have the same <em>average<\/em> kinetic energy, even if their molar masses differ. However, lighter molecules move faster on average (greater speed), because kinetic energy is (1\/2)mv\u00b2.<\/p>\n<h2>Boyle\u2019s Law, Charles\u2019s Law, and Gay-Lussac\u2019s Law<\/h2>\n<p>These laws describe relationships between two variables while holding the others constant.<\/p>\n<p><strong>Boyle\u2019s Law (P\u2013V relationship):<\/strong> At constant temperature and moles, pressure is inversely proportional to volume.<\/p>\n<p><strong>P\u2081V\u2081 = P\u2082V\u2082<\/strong><\/p>\n<p>If volume decreases, pressure increases (assuming T and n constant).<\/p>\n<p><strong>Charles\u2019s Law (V\u2013T relationship):<\/strong> At constant pressure and moles, volume is directly proportional to absolute temperature.<\/p>\n<p><strong>V\u2081\/T\u2081 = V\u2082\/T\u2082<\/strong><\/p>\n<p>Temperature must be in Kelvin. Heating a gas expands it at constant pressure.<\/p>\n<p><strong>Gay-Lussac\u2019s Law (P\u2013T relationship):<\/strong> At constant volume and moles, pressure is directly proportional to absolute temperature.<\/p>\n<p><strong>P\u2081\/T\u2081 = P\u2082\/T\u2082<\/strong><\/p>\n<p>Heating a gas in a rigid container increases its pressure.<\/p>\n<p><strong>NMAT speed tip:<\/strong> For direct relationships (V\u2013T, P\u2013T): increase one \u2192 increase the other. For inverse (P\u2013V): increase one \u2192 decrease the other.<\/p>\n<h2>Combined Gas Law<\/h2>\n<p>The combined gas law merges Boyle\u2019s, Charles\u2019s, and Gay-Lussac\u2019s laws when moles are constant:<\/p>\n<p><strong>(P\u2081V\u2081)\/T\u2081 = (P\u2082V\u2082)\/T\u2082<\/strong><\/p>\n<p>This is common in NMAT problems where pressure, volume, and temperature change simultaneously. Always convert temperatures to Kelvin before solving. Be careful with consistent units (e.g., both pressures in atm, both volumes in liters).<\/p>\n<h2>Avogadro\u2019s Law and Molar Volume<\/h2>\n<p><strong>Avogadro\u2019s Law:<\/strong> At constant temperature and pressure, volume is directly proportional to the number of moles.<\/p>\n<p><strong>V\u2081\/n\u2081 = V\u2082\/n\u2082<\/strong><\/p>\n<p><strong>Key idea:<\/strong> If you double the moles of gas (at same T and P), the volume doubles.<\/p>\n<p><strong>Molar volume at STP:<\/strong> In many exam contexts, STP is defined as 1 atm and 0\u00b0C (273 K), where 1 mole of an ideal gas occupies approximately <strong>22.4 L<\/strong>.<\/p>\n<p>Some sources define \u201cstandard\u201d conditions slightly differently (e.g., 1 bar), but NMAT-style problems typically use the classic 22.4 L at 1 atm and 0\u00b0C unless specified otherwise.<\/p>\n<h2>Ideal Gas Law: PV = nRT<\/h2>\n<p>The most powerful single equation for gases is the <strong>ideal gas law<\/strong>:<\/p>\n<p><strong>PV = nRT<\/strong><\/p>\n<p>Where:<\/p>\n<ul>\n<li>P = pressure<\/li>\n<li>V = volume<\/li>\n<li>n = moles<\/li>\n<li>T = temperature (Kelvin)<\/li>\n<li>R = gas constant<\/li>\n<\/ul>\n<p><strong>Common R values (use the one that matches your units):<\/strong><\/p>\n<ul>\n<li>R = 0.0821 L\u00b7atm\u00b7mol\u207b\u00b9\u00b7K\u207b\u00b9<\/li>\n<li>R = 62.4 L\u00b7torr\u00b7mol\u207b\u00b9\u00b7K\u207b\u00b9<\/li>\n<li>R = 8.314 J\u00b7mol\u207b\u00b9\u00b7K\u207b\u00b9 (when using energy units)<\/li>\n<\/ul>\n<p><strong>NMAT pattern:<\/strong> If given grams of gas, you often need to convert to moles first using molar mass. Then solve for the missing variable.<\/p>\n<p><strong>Density form (very useful):<\/strong> From PV = nRT and n = m\/M (mass\/molar mass), you can derive:<\/p>\n<p><strong>Density (d) = (PM)\/(RT)<\/strong><\/p>\n<p>This helps compare densities of gases at the same T and P: density is proportional to molar mass.<\/p>\n<h2>Dalton\u2019s Law of Partial Pressures<\/h2>\n<p>For a mixture of non-reacting gases in the same container, the total pressure equals the sum of individual partial pressures:<\/p>\n<p><strong>P<sub>total<\/sub> = P\u2081 + P\u2082 + P\u2083 + \u2026<\/strong><\/p>\n<p>The partial pressure of a gas is the pressure it would exert if it alone occupied the container at the same temperature.<\/p>\n<p><strong>Mole fraction relationship:<\/strong><\/p>\n<p><strong>P<sub>i<\/sub> = X<sub>i<\/sub> \u00b7 P<sub>total<\/sub><\/strong><\/p>\n<p>where X<sub>i<\/sub> = n<sub>i<\/sub> \/ n<sub>total<\/sub>.<\/p>\n<p><strong>Collection of gas over water:<\/strong> A classic problem type. If a gas is collected over water, the measured pressure includes water vapor.<\/p>\n<p><strong>P<sub>gas<\/sub> = P<sub>total<\/sub> \u2212 P<sub>H2O<\/sub><\/strong><\/p>\n<p>You must subtract the vapor pressure of water (given in a table or in the problem) to find the dry gas pressure.<\/p>\n<h2>Real Gases: When the Ideal Model Fails<\/h2>\n<p>Real gases deviate from ideal behavior when the ideal assumptions fail\u2014mainly when particle volume and intermolecular forces are no longer negligible.<\/p>\n<p><strong>Greatest deviations occur at:<\/strong><\/p>\n<ul>\n<li><strong>High pressure<\/strong> (particles are closer together; volume matters)<\/li>\n<li><strong>Low temperature<\/strong> (particles move slower; attractions matter more)<\/li>\n<\/ul>\n<p><strong>How deviations happen conceptually:<\/strong><\/p>\n<ul>\n<li>Attractions between particles can reduce measured pressure because particles pull each other away from the walls.<\/li>\n<li>Finite particle volume reduces the free space available for motion, effectively altering volume.<\/li>\n<\/ul>\n<p>For NMAT, you are usually not required to use advanced real-gas equations, but you should know <em>when<\/em> ideal assumptions are least valid and why.<\/p>\n<h2>High-Yield Problem-Solving Strategy for NMAT<\/h2>\n<p>Many gas-law mistakes come from avoidable errors. Use this checklist:<\/p>\n<ul>\n<li><strong>Convert temperature to Kelvin<\/strong> before plugging into formulas.<\/li>\n<li><strong>Keep units consistent<\/strong> (don\u2019t mix atm with kPa unless converting).<\/li>\n<li><strong>Identify what is held constant<\/strong> (T? P? V? n?) to choose the simplest law.<\/li>\n<li><strong>Use ratios<\/strong> (Boyle\/Charles\/Gay-Lussac\/Combined law) when moles are constant and you\u2019re comparing two states.<\/li>\n<li><strong>Use PV = nRT<\/strong> when you have a single state and can compute moles.<\/li>\n<li><strong>Watch significant information<\/strong>: \u201ccollected over water,\u201d \u201crigid container,\u201d \u201cpiston moves freely,\u201d \u201csealed container,\u201d and \u201csame conditions.\u201d<\/li>\n<\/ul>\n<p><strong>Common conceptual questions:<\/strong><\/p>\n<ul>\n<li>If temperature increases in a sealed rigid container, what happens to pressure? (It increases.)<\/li>\n<li>At the same temperature, which gas has faster molecules: He or O\u2082? (He, because lower molar mass.)<\/li>\n<li>Which conditions favor ideal behavior? (Low pressure, high temperature.)<\/li>\n<li>Why does water have a high boiling point? (Strong hydrogen bonding.)<\/li>\n<\/ul>\n<h2>Quick NMAT Mini-Review Summary<\/h2>\n<ul>\n<li><strong>Solids<\/strong>: fixed shape\/volume, low compressibility; particles vibrate.<\/li>\n<li><strong>Liquids<\/strong>: fixed volume, variable shape; particles flow.<\/li>\n<li><strong>Gases<\/strong>: variable shape\/volume, high compressibility; particles move randomly.<\/li>\n<li><strong>Phase changes<\/strong>: temperature constant during melting\/boiling; energy breaks\/form IMFs.<\/li>\n<li><strong>Boyle<\/strong>: P inversely with V (T constant).<\/li>\n<li><strong>Charles<\/strong>: V directly with T (P constant).<\/li>\n<li><strong>Gay-Lussac<\/strong>: P directly with T (V constant).<\/li>\n<li><strong>Combined<\/strong>: (PV)\/T constant (n constant).<\/li>\n<li><strong>Ideal gas law<\/strong>: PV = nRT.<\/li>\n<li><strong>Dalton<\/strong>: total pressure is sum of partial pressures.<\/li>\n<li><strong>Real gas deviations<\/strong>: high P, low T.<\/li>\n<\/ul>\n<p>Mastering these ideas gives you both conceptual strength and computational speed\u2014exactly what NMAT chemistry questions reward.<\/p>\n<h2>Problem Sets<\/h2>\n<h2>Set 1: States of Matter and Phase Changes (Conceptual)<\/h2>\n<ol>\n<li>Which state of matter has a definite volume but no definite shape?<\/li>\n<li>Which state of matter is most compressible?<\/li>\n<li>Which phase change is endothermic: condensation or vaporization?<\/li>\n<li>During a phase change on a heating curve, why does temperature remain constant?<\/li>\n<li>Which intermolecular force is strongest in typical molecular substances: London dispersion, dipole\u2013dipole, or hydrogen bonding?<\/li>\n<li>Which has stronger intermolecular forces: CH<sub>4<\/sub> or C<sub>4<\/sub>H<sub>10<\/sub>?<\/li>\n<li>Boiling occurs when the vapor pressure of a liquid equals what external quantity?<\/li>\n<li>What phase change is the reverse of sublimation?<\/li>\n<li>Which generally has higher surface tension: a liquid with stronger IMFs or weaker IMFs?<\/li>\n<li>Which statement is true at the particle level for gases (choose the best): particles are closely packed, particles move randomly and are far apart, particles vibrate in fixed positions?<\/li>\n<\/ol>\n<h2>Set 2: Gas Law Relationships (Boyle\/Charles\/Gay-Lussac\/Combined)<\/h2>\n<ol>\n<li>A gas has P<sub>1<\/sub> = 2.00 atm and V<sub>1<\/sub> = 3.00 L at constant temperature. If the pressure changes to P<sub>2<\/sub> = 1.20 atm, what is V<sub>2<\/sub>?<\/li>\n<li>A balloon has V<sub>1<\/sub> = 2.50 L at T<sub>1<\/sub> = 300 K (constant pressure). If the temperature increases to 360 K, what is V<sub>2<\/sub>?<\/li>\n<li>A sealed rigid container holds a gas at P<sub>1<\/sub> = 0.80 atm and T<sub>1<\/sub> = 250 K. If heated to 400 K, what is P<sub>2<\/sub>?<\/li>\n<li>A gas is compressed from V<sub>1<\/sub> = 5.0 L to V<sub>2<\/sub> = 2.0 L at constant temperature. If P<sub>1<\/sub> = 1.0 atm, what is P<sub>2<\/sub>?<\/li>\n<li>Use the combined gas law: A gas has P<sub>1<\/sub> = 1.50 atm, V<sub>1<\/sub> = 4.00 L, T<sub>1<\/sub> = 300 K. It changes to P<sub>2<\/sub> = 1.00 atm and T<sub>2<\/sub> = 350 K. What is V<sub>2<\/sub>?<\/li>\n<li>A gas sample is cooled from 27\u00b0C to -33\u00b0C at constant pressure. If V<sub>1<\/sub> = 3.60 L, what is V<sub>2<\/sub>? (Use Kelvin.)<\/li>\n<li>A gas in a rigid tank has its temperature doubled (in Kelvin). What happens to its pressure (assume ideal behavior)?<\/li>\n<li>A piston allows volume to change freely while pressure stays constant. If the gas temperature decreases from 500 K to 400 K, does the volume increase, decrease, or stay the same?<\/li>\n<\/ol>\n<h2>Set 3: Ideal Gas Law (PV = nRT)<\/h2>\n<ol>\n<li>How many moles of gas are in a 10.0 L container at 2.00 atm and 300 K? (Use R = 0.0821 L\u00b7atm\u00b7mol<sup>-1<\/sup>\u00b7K<sup>-1<\/sup>.)<\/li>\n<li>What is the pressure of 0.750 mol of gas in a 5.00 L container at 298 K?<\/li>\n<li>What volume does 1.20 mol of gas occupy at 1.00 atm and 273 K?<\/li>\n<li>A 4.00 g sample of He is placed in a 2.00 L container at 300 K. What is the pressure? (Molar mass He = 4.00 g\/mol.)<\/li>\n<li>At constant T and V, moles of gas are tripled. What happens to pressure?<\/li>\n<li>Using the density relation d = (PM)\/(RT): At 1.00 atm and 300 K, which has higher density, N<sub>2<\/sub> or CO<sub>2<\/sub>, and why?<\/li>\n<\/ol>\n<h2>Set 4: Dalton\u2019s Law and Gas Over Water<\/h2>\n<ol>\n<li>A mixture contains O<sub>2<\/sub> at 0.40 atm and N<sub>2<\/sub> at 0.55 atm. What is the total pressure?<\/li>\n<li>The total pressure of a gas mixture is 1.20 atm. The mole fraction of CO<sub>2<\/sub> is 0.25. What is P<sub>CO2<\/sub>?<\/li>\n<li>A gas is collected over water at a total pressure of 760 mmHg. If the vapor pressure of water is 24 mmHg, what is the dry gas pressure?<\/li>\n<li>A mixture contains 2.0 mol He and 1.0 mol Ne at the same T and V. What is the mole fraction of He?<\/li>\n<li>In the mixture in Q4, if P<sub>total<\/sub> = 3.00 atm, what is P<sub>He<\/sub>?<\/li>\n<\/ol>\n<h2>Set 5: Real vs Ideal Gases (Concept + Quick Reasoning)<\/h2>\n<ol>\n<li>Under which conditions do gases deviate most from ideal behavior: high T\/low P or low T\/high P?<\/li>\n<li>Give one reason measured pressure of a real gas can be lower than ideal pressure under the same conditions.<\/li>\n<li>Which gas is expected to deviate more from ideal behavior at the same T and P: NH<sub>3<\/sub> or He? (Explain briefly.)<\/li>\n<li>True or False: At the same temperature, all gases have the same average kinetic energy.<\/li>\n<li>At STP (1 atm, 273 K), what is the approximate molar volume of an ideal gas?<\/li>\n<\/ol>\n<h2>Answer Keys<\/h2>\n<h2>Set 1 Answer Key<\/h2>\n<ol>\n<li>Liquid<\/li>\n<li>Gas<\/li>\n<li>Vaporization (endothermic); condensation is exothermic<\/li>\n<li>Heat energy is used to overcome intermolecular forces (change potential energy), not increase kinetic energy<\/li>\n<li>Hydrogen bonding<\/li>\n<li>C<sub>4<\/sub>H<sub>10<\/sub> (larger molecule \u2192 stronger London dispersion)<\/li>\n<li>External (atmospheric) pressure<\/li>\n<li>Deposition<\/li>\n<li>Stronger IMFs<\/li>\n<li>Particles move randomly and are far apart<\/li>\n<\/ol>\n<h2>Set 2 Answer Key<\/h2>\n<ol>\n<li>V<sub>2<\/sub> = (P<sub>1<\/sub>V<sub>1<\/sub>)\/P<sub>2<\/sub> = (2.00 \u00d7 3.00)\/1.20 = 5.00 L<\/li>\n<li>V<sub>2<\/sub> = V<sub>1<\/sub>(T<sub>2<\/sub>\/T<sub>1<\/sub>) = 2.50(360\/300) = 3.00 L<\/li>\n<li>P<sub>2<\/sub> = P<sub>1<\/sub>(T<sub>2<\/sub>\/T<sub>1<\/sub>) = 0.80(400\/250) = 1.28 atm<\/li>\n<li>P<sub>2<\/sub> = P<sub>1<\/sub>(V<sub>1<\/sub>\/V<sub>2<\/sub>) = 1.0(5.0\/2.0) = 2.5 atm<\/li>\n<li>V<sub>2<\/sub> = (P<sub>1<\/sub>V<sub>1<\/sub>T<sub>2<\/sub>)\/(P<sub>2<\/sub>T<sub>1<\/sub>) = (1.50\u00d74.00\u00d7350)\/(1.00\u00d7300) = 7.00 L<\/li>\n<li>Convert: T<sub>1<\/sub> = 27\u00b0C = 300 K; T<sub>2<\/sub> = -33\u00b0C = 240 K<br \/>\nV<sub>2<\/sub> = V<sub>1<\/sub>(T<sub>2<\/sub>\/T<sub>1<\/sub>) = 3.60(240\/300) = 2.88 L<\/li>\n<li>Pressure doubles (P \u221d T when V is constant)<\/li>\n<li>Volume decreases (V \u221d T when P is constant)<\/li>\n<\/ol>\n<h2>Set 3 Answer Key<\/h2>\n<ol>\n<li>n = PV\/RT = (2.00\u00d710.0)\/(0.0821\u00d7300) = 20.0\/24.63 \u2248 0.812 mol<\/li>\n<li>P = nRT\/V = (0.750\u00d70.0821\u00d7298)\/5.00<br \/>\n= (0.750\u00d724.466)\/5.00 = 18.35\/5.00 \u2248 3.67 atm<\/li>\n<li>V = nRT\/P = (1.20\u00d70.0821\u00d7273)\/1.00<br \/>\n= 1.20\u00d722.413 \u2248 26.9 L<\/li>\n<li>n = 4.00 g \/ (4.00 g\/mol) = 1.00 mol<br \/>\nP = nRT\/V = (1.00\u00d70.0821\u00d7300)\/2.00 = 24.63\/2.00 = 12.3 atm<\/li>\n<li>Pressure triples (P \u221d n when T and V are constant)<\/li>\n<li>CO<sub>2<\/sub> has higher density because it has a larger molar mass (44 g\/mol vs 28 g\/mol), so d \u221d M at fixed P and T<\/li>\n<\/ol>\n<h2>Set 4 Answer Key<\/h2>\n<ol>\n<li>P<sub>total<\/sub> = 0.40 + 0.55 = 0.95 atm<\/li>\n<li>P<sub>CO2<\/sub> = X<sub>CO2<\/sub>\u00b7P<sub>total<\/sub> = 0.25\u00d71.20 = 0.30 atm<\/li>\n<li>P<sub>gas<\/sub> = 760 \u2212 24 = 736 mmHg<\/li>\n<li>X<sub>He<\/sub> = 2.0\/(2.0+1.0) = 2\/3 \u2248 0.667<\/li>\n<li>P<sub>He<\/sub> = X<sub>He<\/sub>\u00b7P<sub>total<\/sub> = (2\/3)\u00d73.00 = 2.00 atm<\/li>\n<\/ol>\n<h2>Set 5 Answer Key<\/h2>\n<ol>\n<li>Low T \/ High P<\/li>\n<li>Intermolecular attractions pull particles inward, reducing wall-collision force and lowering measured pressure<\/li>\n<li>NH<sub>3<\/sub> (polar, can hydrogen bond) deviates more than He (very weak attractions)<\/li>\n<li>True<\/li>\n<li>Approximately 22.4 L\/mol<\/li>\n<\/ol>\n<hr data-start=\"4416\" data-end=\"4419\" \/>\n<blockquote class=\"wp-embedded-content\" data-secret=\"qVJxlJlKsA\"><p><a href=\"https:\/\/3d-universal.com\/en\/blogs\/nmat-chemistry-review.html\">NMAT Chemistry Review: NMAT Study Guide<\/a><\/p><\/blockquote>\n<p><iframe loading=\"lazy\" class=\"wp-embedded-content\" sandbox=\"allow-scripts\" security=\"restricted\" style=\"position: absolute; visibility: hidden;\" title=\"&#8220;NMAT Chemistry Review: NMAT Study Guide&#8221; &#8212; Study English at 3D ACADEMY, a Language School in Cebu, Philippines\" src=\"https:\/\/3d-universal.com\/en\/blogs\/nmat-chemistry-review.html\/embed#?secret=yU24MCDlIX#?secret=qVJxlJlKsA\" data-secret=\"qVJxlJlKsA\" width=\"500\" height=\"282\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\"><\/iframe><\/p>\n","protected":false},"excerpt":{"rendered":"","protected":false},"author":1,"featured_media":20678,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_kad_blocks_custom_css":"","_kad_blocks_head_custom_js":"","_kad_blocks_body_custom_js":"","_kad_blocks_footer_custom_js":"","footnotes":""},"categories":[116],"tags":[],"class_list":["post-20675","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-nmat-chemistry-review"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v25.6 (Yoast SEO v25.6) - 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