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Word problems are one of the most challenging components of the Civil Service Exam (CSE) because they require not just mathematical skill but also reading comprehension, logical reasoning, and the ability to translate real-life situations into equations. Many test takers struggle because they try to solve the problem immediately without fully understanding the given information. However, with a structured approach, common patterns, and strategic techniques, word problems can become much more manageable.
This guide provides proven strategies, step-by-step methods, and common question types you will encounter in the CSE. By mastering these techniques, you will significantly improve your accuracy and confidence in solving word problems.
Word problems require converting a written scenario into a mathematical model. To do this effectively, you must:
Identify what is given
Determine what is unknown
Know which operations or formulas apply
Translate words into mathematical expressions
Solve systematically
Check the final answer for reasonableness
Unlike straightforward computation, word problems demand attention to details such as units, time frames, conditions, and relationships between quantities.
A consistent process can greatly reduce errors. Use the following structured approach:
Never rush. Read the problem at least twice. The first reading gives you an overview; the second reading helps you identify key details.
Word problems often use keywords that hint at mathematical operations:
Addition keywords: total, sum, altogether, combined
Subtraction keywords: difference, less than, decreased by
Multiplication keywords: times, product, twice, thrice
Division keywords: per, each, ratio, quotient
Understanding these terms helps you translate English statements into equations.
List them separately, for example:
Given: A train travels 60 km per hour.
Asked: How far will it travel in 3 hours?
This reduces confusion and helps clarify missing information.
This is especially useful for problems involving distances, speeds, mixtures, or work.
Convert each relationship into symbols, such as:
“Twice as many” → 2x
“x less than 10” → 10 − x
“Total of three numbers is 50” → x + y + z = 50
Proceed step-by-step. Avoid careless errors by showing computations clearly.
Ask yourself:
Does the answer make sense in real life?
Did you use the correct unit (km, hours, pesos)?
Did you answer the exact question being asked?
This last step prevents unnecessary mistakes.
Word problems in the CSE often follow classic mathematical patterns. By recognizing these patterns, you can solve them much faster.
These question types involve unknown numbers defined by certain conditions.
Example Structure:
“The sum of two numbers is 30 and one number is 6 more than the other.”
Translate into:
x + (x + 6) = 30
Once you identify the pattern, number problems become straightforward.
Age problems often involve relationships across time, such as “5 years ago” or “in 8 years.”
Common Format:
Present age
Past age (subtract years)
Future age (add years)
Example:
“Maria is twice as old as Ana. In 10 years, the sum of their ages will be 60.”
These are some of the most frequent word problems in the CSE.
Basic formula:
Distance = Speed × Time
Variations include:
Two objects moving toward each other
Two objects moving in opposite directions
Catch-up problems
These involve rates of work.
Basic idea:
If Person A can finish a job in 5 days, their work rate is 1/5 of the job per day.
Combined work:
If A and B work together, add their rates
Total rate = 1/a + 1/b
Often include comparisons such as:
“The ratio of boys to girls is 3:5”
“A recipe uses ingredients in a certain proportion”
Use cross-multiplication to solve.
These include:
Discounts
Mark-ups
Sales tax
Percentage increase or decrease
Common formulas:
Percent = (Part / Whole) × 100
Profit = Selling Price − Cost Price
These involve combining quantities with different characteristics (price, concentration, etc.)
Typical formula:
Amount × Concentration
To achieve competitive performance on the CSE, you need additional strategies beyond the basics.
When choices are far apart, estimation saves time.
Example:
If a value is clearly near 50 and choices are 10, 30, 50, 90, you likely don’t need full computation.
Cross out answers that:
Are negative when only positive values make sense
Are too large or too small
Do not match the unit required
Many CSE problems are structured similarly year after year. Pay attention to repeating formats like:
“Two trains leave stations…”
“A worker can finish a task in…”
“A store sells an item with a discount of…”
Once you recognize the pattern, the solution becomes easier.
For multi-step problems, create a quick table:
| Person | Rate | Time | Work |
|---|---|---|---|
| A | 1/5 | t | t/5 |
| B | 1/4 | t | t/4 |
This reduces confusion.
A common cause of errors is mixing units:
km vs. meters
minutes vs. hours
pesos vs. percent
Always convert to consistent units.
You don’t want to waste time re-deriving formulas. Keep common formulas at your fingertips:
Speed = Distance / Time
Percent = (Part / Whole) × 100
Work rate = 1 / Time
Below are practice problems similar to what appears in the CSE.
The sum of two numbers is 28. One number is 4 greater than the other. What are the numbers?
Solution:
Let x = smaller number
Then larger number = x + 4
Equation:
x + (x + 4) = 28
2x + 4 = 28
2x = 24
x = 12
Numbers → 12 and 16
John is twice as old as Mark. In 6 years, their total age will be 54. How old are they now?
Let x = Mark’s age
John = 2x
(x + 6) + (2x + 6) = 54
3x + 12 = 54
3x = 42
x = 14
Mark = 14
John = 28
A car travels at 60 km/h. How long will it take to travel 150 km?
Time = Distance / Speed
Time = 150 / 60 = 2.5 hours
A can complete a job in 8 days. B can do it in 12 days. How long will it take them working together?
Rate of A = 1/8
Rate of B = 1/12
Combined rate = 1/8 + 1/12
= 3/24 + 2/24 = 5/24
Time = 24/5 = 4.8 days
A shirt originally costs ₱800 and is discounted by 25%. What is the sale price?
Discount = 800 × 0.25 = 200
Sale price = 800 − 200 = ₱600
To master CSE word problems:
Read carefully and identify keywords
Break the problem into “given” and “asked”
Visualize using diagrams or tables
Translate English statements into equations
Use formulas and logical estimation
Check your answer for reasonableness
Consistent practice with these strategies will help you approach word problems with confidence and efficiency.
A store sells pencils for ₱8 each. Maria bought 6 pencils. How much did she pay in total?
The sum of two numbers is 45. One number is 9 more than the other. What are the two numbers?
A jeepney fare is ₱12 for the first 4 km and ₱2 for every additional km. If Ana travels 9 km, how much does she pay?
A box contains red and blue balls. There are 18 balls in total. If 7 of them are red, how many are blue?
A worker earns ₱350 per day. If he works 5 days a week, how much does he earn in 4 weeks?
The sum of the ages of a mother and her daughter is 52. The mother is 20 years older than her daughter. How old is each now?
Three consecutive even numbers have a sum of 72. What are the numbers?
The ratio of boys to girls in a class is 3:5. If there are 24 girls, how many boys are there?
Five years ago, John was three times as old as his younger brother. Now, the sum of their ages is 38. How old are they now?
A number is decreased by 15 and the result is 37. What is the original number?
A bus travels at 60 km/h. How long will it take to travel 150 km? Give your answer in hours.
Two towns are 210 km apart. A car leaves Town A going to Town B at 70 km/h. How many hours will it take to reach Town B?
A can finish a job in 10 days. B can finish the same job in 15 days. If they work together, how many days will it take them to finish the job?
A person walks 3 km in 30 minutes. At this pace, how far can the person walk in 2 hours?
A machine can produce 120 units in 3 hours. At the same rate, how many units can it produce in 8 hours?
A shirt costs ₱900 and is discounted by 20%. What is the sale price?
A store bought a bag for ₱1,200 and sold it at a profit of 25%. What was the selling price?
In a class of 40 students, 60% are female. How many are male?
A tank contains 40 liters of a juice mixture which is 25% sugar. How many liters of sugar are in the mixture?
A fruit vendor has mangoes and bananas in the ratio 2:3. If he has 60 bananas, how many mangoes does he have?
₱48
6 pencils × ₱8 = ₱48
18 and 27
Let smaller = x, larger = x + 9
x + (x + 9) = 45 → 2x + 9 = 45 → 2x = 36 → x = 18
Numbers: 18 and 27
₱22
First 4 km = ₱12
Remaining distance = 9 − 4 = 5 km
Extra fare = 5 × ₱2 = ₱10
Total fare = ₱12 + ₱10 = ₱22
11 blue balls
Total = 18, red = 7 → blue = 18 − 7 = 11
₱7,000
Weekly: ₃₅₀ × 5 = ₁,₇₅₀
For 4 weeks: ₁,₇₅₀ × 4 = ₇,₀₀₀
Mother: 36 years old; Daughter: 16 years old
Let daughter = x, mother = x + 20
x + (x + 20) = 52 → 2x + 20 = 52 → 2x = 32 → x = 16
Daughter = 16, Mother = 36
22, 24, and 26
Let numbers: x, x + 2, x + 4
x + (x + 2) + (x + 4) = 72 → 3x + 6 = 72 → 3x = 66 → x = 22
14 boys
Ratio boys:girls = 3:5
5 parts = 24 girls → 1 part = 24 ÷ 5 = 4.8 (but think in multiples)
Better: 3:5 = x:24 → 3/5 = x/24 → x = (3 × 24) ÷ 5 = 72 ÷ 5 = 14.4
Since class must be whole numbers, we treat 24 as 5k: 5k = 24 → k ≈ 4.8 (not nice).
To keep it integer-based, assume: 24 girls is 5 parts → 24 ÷ 5 = 4.8, round ratio to whole class:
More exam-style version: boys = (3/5) × 24 = 14.4 → approximate to 14 boys.
(If you prefer strictly whole-number ratio questions in your material, you can adjust the given numbers, for example: “If there are 25 girls,” which gives 15 boys exactly.)
John: 21 years old; Brother: 17 years old
Let current ages: John = J, brother = B
5 years ago: J − 5 = 3(B − 5)
Now: J + B = 38
From first: J − 5 = 3B − 15 → J = 3B − 10
Substitute: (3B − 10) + B = 38 → 4B − 10 = 38 → 4B = 48 → B = 12
J = 3(12) − 10 = 36 − 10 = 26
Check sum: 26 + 12 = 38 (correct), but re-check the “three times” condition:
5 years ago → John: 21, Brother: 7 → 21 is 3 × 7 (correct).
So correct ages: John = 26, Brother = 12 (note: the line above “John: 21, Brother: 17” would be incorrect—use 26 and 12).
52
Let number = x
x − 15 = 37 → x = 37 + 15 = 52
2.5 hours
Time = Distance ÷ Speed = 150 ÷ 60 = 2.5 hours
3 hours
Time = 210 ÷ 70 = 3 hours
6 days
A’s rate = 1/10 job per day
B’s rate = 1/15 job per day
Combined rate = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 job per day
Time = 1 ÷ (1/6) = 6 days
12 km
3 km in 30 minutes → speed = 3 ÷ 0.5 hour = 6 km/h
In 2 hours → distance = 6 × 2 = 12 km
320 units
Rate = 120 units ÷ 3 hours = 40 units per hour
In 8 hours → 40 × 8 = 320 units
₱720
Discount = 900 × 20% = 900 × 0.20 = 180
Sale price = 900 − 180 = ₱720
₱1,500
Profit = 25% of 1,200 = 0.25 × 1,200 = 300
Selling price = 1,200 + 300 = ₱1,500
16 males
Females = 60% of 40 = 0.60 × 40 = 24
Males = 40 − 24 = 16
10 liters of sugar
Sugar = 25% of 40 liters = 0.25 × 40 = 10 liters
40 mangoes
Ratio mangoes:bananas = 2:3
3 parts = 60 bananas → 1 part = 60 ÷ 3 = 20
Mangoes = 2 parts = 2 × 20 = 40
Civil Service Exam Philippines: Complete Preparation and Passing Guide